C语言嵌入informix基础入门示例讲解
#include
#include
#include
#include
$struct _db_person
{
char name[30+1];
char card[12+1];
int age;
};
char *trim(char *str)
{
char *p, *buffer;
int len;
if( NULL!=str )
{
len = strlen(str);
if( len > 0 )
{
buffer=(char *)malloc(sizeof(char)*(len+1));
if( NULL != buffer )
{
memmove(buffer, str, len);
buffer[len]=0;
p = buffer + len - 1;
while( (p != buffer) && ((*p > 0x00) && (*p <= ' ')) )
*(p--) = 0;
p = buffer;
while( (*p > 0x00) && (*p <= ' ') )
p++;
strcpy(str, p);
free(buffer);
}
}
}
return str;
}
int GetData(struct _db_person *pps)
{
char strage[20];
memset(pps, 0, sizeof(struct _db_person));
printf("enter name
fgets(pps->name,sizeof(pps->name),stdin);
trim(pps->name);
if( strlen(pps->name) == 0 )
return -1;
printf("enter card no
fgets(pps->card,sizeof(pps->card),stdin);
trim(pps->card);
if( strlen(pps->card) == 0 )
return -2;
printf("enter age
fgets(strage,sizeof(strage),stdin);
trim(strage);
if( strlen(strage) == 0 )
return -3;
pps->age = atoi(strage);
return 0;
}
int main(void)
{
$struct _db_person dbps;
$database exec01;
if( SQLCODE != 0 )
{
printf("open demo1 failure,SQLCODE=%d
",SQLCODE);
return -1;
}
while( 1 )
{
if( GetData(&dbps)<0 )
break;
$insert into person(name, card, age) values($dbps.name, $dbps.card, $dbps.age);
printf("insert data result: SQLCODE=%d
",SQLCODE);
$declare vcursor cursor for select name, card, age into $dbps.name, $dbps.card, $dbps.age from person;
printf("declare vcursor result: SQLCODE=%d
",SQLCODE);
$open vcursor;
printf("open vcursor result: SQLCODE=%d
",SQLCODE);
if( 0==SQLCODE )
{
while( 1 )
{
$fetch vcursor;
if( 0==SQLCODE )
{
printf("name=[%s],card=[%s],age=[%d]
",dbps.name,dbps.card,dbps.age);
}
else
{
if( SQLCODE==100 )
printf("fetch end!
");
else
printf("fetch failure!SQLCODE=%d
",SQLCODE);
break;
}
}
}
$close vcursor;
$free vcursor;
}
$disconnect current;
return 0;
}